y=x^2+8x+16 vertex?

Question

i need help on finding the vertex of the problem fast and i just need the answer pretty please

Answer 1

Nadia says: x coordinate of vertex is -b/2a =-8/2(1)=-4 and she's right  BUT SHE SHOULD HAVE SAID

x coordinate of vertex is -b/2(a) =-8/(2(1))=-4.

 

A multi-factor denominator MUST be fully parenthesized in this platform so that the formula is not misinterpreted as one half of negative b, and then multiplying said quotient by a.

 

In this case, her imperfect calculation still worked, simply because a=1.  

 

Also, I trust that you are looking beyond the mere satisfaction of getting the right answer, and instead concentrate on the depth of conceptual understanding, part of which is to memorize this formula for x coordinate of a vertex.

Answer 2

y=x^2+8x+16

 

 

here a=1,b=8,c=16

 

x coordinate of vertex is -b/2a =-8/2(1)=-4

 

y=(-4)^2+8(4)+16

  =16+32+16

 =64

 

vertex is(-4,64)