
Jonathan W. answered 02/18/14
Tutor
4.9
(276)
Patient and Knowledgeable Berkeley Grad for Math and Science Tutoring
I can get you started with the partial derivative ∂R/∂x = abx^(a-1)y^b. Have you gotten that far?
Garrick N.
Nevermind, I've got it now.
Report
02/18/14
Garrick N.
Am I to just add ∂R/∂x = abx^(a-1)y^b and ∂R/∂y = b^2x^ay^(b-1) together for the first part?
And, I'm not sure where to start with the second part.
02/18/14