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3(3+c)=2(c-1)

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2 Answers

Hi Karina;
3(3+c)=2(c-1)
Let's distribute the 3 on the left side, and the 2 on the right side...
[(3)(3)]+[(3)(c)]=[(2)(c)]-[(2)(1)]
9+3c=2c-2
Let's subtract 2c from both sides...
9+3c-2c=2c-2-2c
9+c=-2
Let's subtract 9 from both sides...
9+c-9=-2-9
c=-11
3(3+c)=2(c-1)
 
Use distributive property on left and right
 
3*3 + 3*c = 2*c - 2*1
 
9 + 3c = 2c - 2
 
Add -9-2c to both sides
 
c = -11