how to i solve for C i have tried many ways. but im not familiar with the C being in ()

Hi Karina;

3(3+c)=2(c-1)

Let's distribute the 3 on the left side, and the 2 on the right side...

[(3)(3)]+[(3)(c)]=[(2)(c)]-[(2)(1)]

9+3c=2c-2

Let's subtract 2c from both sides...

9+3c-2c=2c-2-2c

9+c=-2

Let's subtract 9 from both sides...

9+c-9=-2-9

c=-11