Algebra II

Question

The functions f and g are defined by f(x)=x² and g(x)=2x, respectively. Which equation is equivalent to h (x)=f(2x)g (-2x) divided by 2 ?

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(1) h(x)=-2x³                      (3)h(x)=x²-2x

(2) h(x)=-8x³                      (4)h(x)=2x²+2x

Answer 1

h(x) = [f(2x)g(-2x)] / 2

       = (2x)²(2(-2x)) / 2

       = (4x² * -4x) / 2

       = -16x³ / 2

       = -8x³