Steve S. answered 02/12/14
Tutor
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Tutoring in Precalculus, Trig, and Differential Calculus
A high diver jumps off a 10 meter platform, model his height above the water at any time after he jumps.
If y is the height above the water, g = -9.8 m/s^2 is the acceleration due to gravity, and x is the time in seconds after the jump, then:
y = -9.8x^2/2 + 10.
That's the equation of a parabola with vertex (0,10) and opening downward. But the real domain is x ≥ 0 seconds; i.e., the right half of the parabola.
Here's a fun video: go to http://www.learner.org/resources/series42.html?pop=yes&pid=549#program_descriptions, click the VOD badge to the right of "2. The Law of Falling Bodies" and watch from position 10:20 and following. The first 10 minutes is interesting too, if you want to go back and see it from the beginning.