Right in equation of the line that passes through the given point and is perpendicular to the graph of the given equation.

Question

(2,-1);y=-2x+1

Answer 1

Since the slope of the given line is -2 the slope we need for the perpendicular line is 1/2

 

Therefore, our line is y = 1/2x + b   All we need now is the y-intercept

 

plug the point (2, -1) into the equation for x and y

 

-1 = 1/2(2) + b

-1 = 1 + b

 

-2 = b

 

ANSWER: y = 1/2x -2

Answer 2

Right in equation...???

Write an equation ...

 

(2,-1);y=-2x+1

 

Your line is in slope intercept form  y = mx + b

where m = -2 is the slope and y-intercept (0,1)

 

A perpendicular line will have a slope that is the

negative reciprocal of this line... m_⊥ = -1/m

So your new line has a slope of -1/-2 = 1/2

 

y = (1/2)x + b   through point (2,-1)

Plug in x=2 and y = -1 into this to solve for b

 

-1 = (1/2)(2) + b

-1 = 1 + b

b = -2

 

Your equation is:  y = (1/2)x - 2