Michael J. answered 12/03/16
Tutor
5
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Understanding all Sines of Triangles
Angle A is opposite to side BC. BC is side a.
Angle B is opposite to side AC. AC is side b.
Angle C is opposite to side AB. AB is side c.
Using the law of sines,
sinA / BC = sinC / AB
Solve for BC.
BCsinC = ABsinA
BC = ABsinA / sinC
a = c(sinA) / [sin(180 - A - B)]
Plug in the value of c, A, and B into the bolded equation.