IMPORTANT PLEASE HELP! URGENT!

Question

The width of the rectangle is x+7. Length: 4x. If the perimeter is 44 in. What's the area of the rectangle? THE ANSWER MUST BE 12O INCHES.

Answer 1

Let L = the length of the rectangle

Let W = the width of the rectangle

 

The formula of the perimeter of a rectangle is 2L + 2W

The formula for the area of a rectangle is L*W

 

We are told W = x+7

We are told L = 4x

We are told the perimeter = 44

 

Therefore:

2L+2W = 44

2(4x) + 2(x+7) = 44

8x + 2x + 14 = 44

10x + 14 = 44

10x = 44 - 14

10x = 30

x = 3

 

Since x = 3, we know W = x + 7 = 10 and L = 4x = 12

 

Now we can calculate the area which is W * L = 10 * 12 = 120.

Answer 2

Hi Neessam.

 

Width of a rectangle = (x+7)inch, Length= 4x inch

 

Perimeter of a rectangle = 2( Length+Width)

                           44 = 2(4x+x+7)

                           44 = 2(5x+7)

                           44  = 10x +14

                           30 = 10x

                            3=x

    Width of a rectangle = x+7= 3+7=10 inch

     Length of a rectangle = 4x= 4(3) =12 inch 

Area of a rectangle= Length* Width= 12 *10= 120 sq Inch.