If y = x/√(7-x2) and x = √(7cosθ), then y = √(7cosθ)/√(7-7cos2θ)
= √(7cosθ)/√(7(1-cos2θ))
= √7√cosθ/(√7√sin2θ)
= √cosθ/ lsinθl
= √cosθ/sinθ (since θ lies in
quadrant 1)