Jesse K. answered 11/13/16
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Plane A
Distance traveled = 2700 miles
time taken = t
Speed of plane A = x mph
Speed = distance /time
x = 2700/t
t = 2700/ x ______ equation 1
Plane B
Distance traveled = 3040 miles
time taken = t
Speed of plane B = x + 85 mph
Speed = distance /time
x +85= 3040/t
t = 3040/ (x+85) ______ equation 2
time taken = t
Speed of plane B = x + 85 mph
Speed = distance /time
x +85= 3040/t
t = 3040/ (x+85) ______ equation 2
Now we can equate equation 1 and 2
2700 / x = 3040/(x+85)
2700(x+85) = 3040 x
2700x + 229500= 3040x
229500=340x
x = 675 mph
substitute x= 675 in equation 1
t = 2700/ x
t= 2700/675
t = 4
So time taken by both plane = 4 hrs