
Kenneth S. answered 11/10/16
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For the inscribed rectangle, let (x,y) be the coordinates of one vertex, both x & y being > 0.
The four vertices of the rectangle would be (±x,±y), in various combinations of signs.
We can say that x2 + y2 = 100 (eq. of circle)...so y2 = 100 -x2.
Consider g(x) = xy2 = x(100 -x2) = 100x - x3 ... a function to be maximized.
Its derivative g'(x) = 100 - 3x2 and its critical point occurs at x = 10/√3, where, BTW, g' < 0 so this C.P. is a maximum.
Thus the dimensions of the rectangle in question are horizontal side = 20/√3 or about 11.547.
Corresponding to the x root, the associated y value is the square root of [100 - 100/3]; this is about 8.165 and so the vertical side of the rectangle in question must be 16.330.