
Kenneth S. answered 11/10/16
Tutor
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Calculus will seem easy if you have the right tutor!
1. y = exey
y' = dy/dx = exey + exeyy' using the product rule
y' (1-exey) = exey
y' = exey / (1-exey) and this can be simplified in various ways, according to taste.
2. Easy...just look up what the derivative of cosec is, and then apply a factor 5,attributed to the chain rule, deriv of argument.