If f(x)=(x^2+1)^x, find f'(x).

Hint if f(x)=(x

^{2}+1)^{x}then the ln(f(x))= xln(x^{2}+1) differentiate both sides with respect to x.d/dx(f)= (1/f) df/dx=d/dx(xln(x

^{2}+1)) use the product rule on the right hand side and then solve for df/dxRegards

Jim

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