ship 1 hits with a 3/8 chance and ship 2 hits with a 5/6 chance but ...

Question

ship 1 hits with a 3/8 chance and ship 2 hits with a 5/6 chance but if ship 1 hits first ship 2 will have a 1/6 chance of hitting what is the probability that ship 1 hits and and ship 2 misses

Answer 1

P(s1 hits) = 3/8

P(s1 misses) = 5/8

P(s2 hits) = 5/6

P(s2 misses) = 1/6

 

P(s1 hits, s2 misses) = P(s1) * P(s2m) = 3/8 * 1/6 = 3/48 = 1/16