The perimeter of a rectangle is 244 feet. If its length is 2 feet longer than twice its width, what are the dimensions of the field?

Question

The perimeter of a rectangle is 244 feet. If its length is 2 feet longer than twice its width, what are the dimensions of the field?

Answer 1

The perimeter of a rectangle is 244 feet:

equation 1:  2L + 2W = 244

 

length is 2 feet longer than twice its width:

equation 2)  L = 2W+2

 

Replace L with 2W+2 in equation 1 and solve for W

 

2(2W+2)+2W = 244

4W+4+2W = 244

6W + 4 = 244

6W = 240

W = 40 ft

 

L = 2W+2 = 82 ft

 

Check:P = 2(L+W)=244

           2(122)=244

           244=244

Answer checks.