Mitiku D. answered 02/04/15
Tutor
4.9
(205)
Effective
Hi Wesley,
the length is 10 more than the width => l = w + 10 ........... eq(1)
perimeter is 80 cm => 2l + 2w = 80cm..............................eq(2)
now substitute eq(1) in to eq(2)
2(w + 10) + 2w = 80
2w + 20 + 2w = 80
4w + 20 -20 = 80 -20
4w = 60
w = 15
l = w + 10 = 15 + 10 = 25
2*15 + 2*25 = 80