What is the probability of a 13 sided die showing side 1 on 4 out of 8 rolls?

Question

I am in a 14 team fantasy league. One team has played the highest scoring opponent 4 out of 8 weeks (13 possible opponents each week). I know there are other factors to get an absolutely accurate probability, but for arguments sake, what are the odds of that happening if all 13 potential opponents scores were randomized each week?

Answer 1

You could solve using the binomial distribution.

 

8C4 * (1/12)^4 * (11/12)^4

=.0024