Inactive Tutor answered 10/30/16
Tutor
New to Wyzant
y = xx^2
ln(y) = ln(xx^2) = x2 ln(x)
taking derivative of both sides with respect to x we have,
y'/y = 2x ln(x)+x
y' = (2x ln(x)+x ) xx^2
Inactive Tutor answered 10/30/16
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