Mark M. answered 10/30/16
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Retired math prof. Very extensive Precalculus tutoring experience.
f(x) = (x-2)[x-(-1-√7i)][x-(-1+√7i)]
= (x-2)[(x+1)+√7i][(x+1)-√7i]
= (x-2)[(x+1)2-(√7i)2]
= (x-2)(x2+2x+1+7)
= (x-2)(x2+2x+8) = x(x2+2x+8) - 2(x2+2x+8)
= x3+2x2+8x-2x2-4x-16
= x3+4x-16