Inactive Tutor answered 01/31/14
Tutor
New to Wyzant
Use the sum and difference identity to find the exact values of sine, cosine, and tangent of 195°=60°+135°.
30°-60°-90° 45°-45°-90°
/| |\
2 / | 1 | \ √(2)
/ | √(3) | \
/ | | \
1 -1
sin(195°)=
sin(60°+135°)=
sin60°cos135°+cos60°sin135°=
(√(3)/2)(-1/√(2))+(1/2)(1/√(2))=
(√(3)/2)(-√(2)/2)+(1/2)(√(2)/2)=
(-√(6)/4)+(√(2)/4)=
(-√(6)/4)+(√(2)/4)=
(√(2)-√(6))/4 = the exact value of sin(195°)
cos(195°)=
cos(195°)=
cos(60°+135°)=
cos60°cos135°-sin60°sin135°=
(1/2)(-√(2)/2)-(√(3)/2)(√(2)/2)=
(-√(2)/4)-(√(6)/4)=
-(√(2)+√(6))/4 = the exact value of cos(195°)
tan(195°)=
sin(195°)/cos(195°) =
-(√(2)-√(6))/(√(2)+√(6)) * (√(2)-√(6))/(√(2)-√(6))=
-(2-2√(12)+6)/(2-6)=
(8-4√(3))/4=
2-√(3) = the exact value of tan(195°)
check:
calculator values radical values
sin(195°)≈ -0.25881904510252 (√(2)-√(6))/4≈ -0.25881904510252
cos(195°)≈ -0.965925826289068 -(√(2)+√(6))/4≈ -0.96592582628907
tan(195°)≈ 0.267949192431122 2-√(3)≈ 0.26794919243112
Arthur D.
01/31/14