Alyssa M.

asked • 10/24/16

Can someone help with this calculus problem?

-A man has 61 clients
-Clients are growing at a rate of 1.8 per year.
-His profits are $631.42 per client per year.
-His profits are dropping $12.41 per client per year.
I need to find the instantaneous rate of change for his profits this year. For an equation to find his yearly profit I got (631.42(61+1.8x))-(12.41(61(1.8x))) I don't know if this is correct but when I factored it and got its derivative I got just -226.062 and I don't feel that's right.
 
I know you have to find the equation to represent his profits, find the derivative, and the plug in 0 for the year to get the rate of change now but I'm not sure what to do with all the numbers and such.

1 Expert Answer

By:

Al P. answered • 10/24/16

Tutor
0 (0)

Online Mathematics tutor

Al P.

The answer i provided S(t) is the instantaneous profit for year t.  So to get the rate of change of those profits, you will need to take the derivative then plug in a year for t.   Hope that helps.
Report

10/24/16

Still looking for help? Get the right answer, fast.

Ask a question for free

Get a free answer to a quick problem.
Most questions answered within 4 hours.

OR

Find an Online Tutor Now

Choose an expert and meet online. No packages or subscriptions, pay only for the time you need.