dont get this one

Duplicate of http://www.wyzant.com/resources/answers/24891/factor_s_2_t_u_9t_2_t_u, which I answered.

dont get this one

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Westford, MA

Salt Lake City, UT

Corry,

the common factor for both are (t-u), we can take it out:

(t-u)(s^2-9t^2)

And because a^2-b^2=(a+b)(a-b), in this case,

s^2-9t^2

=s^2-(3t)^2 [note: s=a, 3t=b in the above formula]

=(s+3t)(s-3t)

So the complete factor for this one is (t-u)(s+3t)(s-3t)

Hope it helps.

Heng

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