Kenneth S. answered • 09/30/16

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As I read it, your original numerator is 8x

^{-2}y^{3 and}the original denominator is 4x

^{½}y^{-2}.8/4 gives coefficient 2

Placing x squared in denominator to rid yourself of the negative exponent, and placing y squared in numerator for the same reason, you now will have

Numerator: 2y

^{5}Denominator: x

^{5/2}To RATIONALIZE DENOMINATOR, multiply both top & bottom by an additional x

^{½ }and you then get the correct answer.^{}