(6t^3+5t^2+9)/(2t+3)

Question

(6t³+5t²+9)÷(2t+3)

11/7/2013 | Brittany from Holdrege, NE | 2 Answers | 0 Votes

Answer 1

3t^2 - 2t + 3

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2t+3 |6t^3 +5t^2 + 0t + 9

-(6t^3 + 9t^2)

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-4t^2 + 0t

- (-4t^2 - 6t)

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6t + 9

-(6t+9)

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0

Answer:

3t^2 - 2t + 3

Answer 2

use long division

divide 2t into 6t^3 and get 3t^2

multiply 3t^2 times 2t+3 and get 6t^3+9t^2

subtract 6t^3+9t^2 from 6t^3+5t^2 and get -4t^2; now bring down the 9 and you have -4t^2+9

divide 2t into -4t^2 and get -2t

multiply -2t times 2t+3 to get -4t^2-6t

subtract -4t^2-6t from -4t^2+9 to get 9+6t or 6t+9

divide 2t into 6t to get 3

3 times 2t+3 gives you 6t+9

subtract to get 0

answer:3t^2-2t+3