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find the comulative distribution function CDF?

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The probability distribution for errors is the binomial distribution B(3, 2/5), the probability distribution function (pdf) is
P(k)= (3 C k) (2/5)k (3/5)3-k,
(3 C k) is the binomial coefficient.
The pdf has 4 values:
P(0)= (3/5)3= .216
P(1)= 3 (2/5)(3/5)2 = .432
P(2)= 3 (2/5)2(3/5) = .288
P(3)= (2/5)3 = .064
The cumulative distribution function (cdf) is the sum of these:
C(0)= .216
C(1)= .216+.432= .648
C(2)= .216+.432+.288 = .936
C(3)= .216+.432+.288+.064 = 1
 
You can use a TI-84 calculator to get these answers directly.