Mark M. answered 09/29/16
Tutor
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Retired Math prof with teaching and tutoring experience in trig.
An equation of the path is y = ax2+bx+c.
y is the height above the horizontal plane at a distance of x feet from the origin.
The points (0,0) and (53,0) are on the graph.
Since (0,0) is on the curve, 0 = a(0)2+b(0)+c. So, c = 0
We have y = ax2+bx
Since (8,9) and (53,0) are on the graph, we get:
64a + 8b = 9
2809a + 53b = 0 (divide by 53 to get 53a+b=0)
So, 64a + 8b = 9
53a + b = 0
From the second equation, b = -53a
So, 64a +8(-53a) = 9 -360a = 9 a = -1/40
b = -53(-1/40) = 53/40
The equation is y = (-1/40)x2 + (53/40)x
Max height when x = -b/(2a) = -(53/40)/[-(1/20)] = 26.5
Max height = (-1/40)(26.5)2+(53/40)(26.5) ≈ 17.6 feet
Gurvir S.
can u have a quick look at my questions05/01/21