Inactive Tutor answered 01/21/14
Tutor
New to Wyzant
OK, L, the first thing to do is to find the slope of the line on which the two points lie.
m = slope = [4 - (-8)]/{(-3) - 3] = 12/(-6) = -2
This means the line on which the points lie (let's call it L1) has the general form
y = -2x + b1 (we'll worry about b later).
Since the other line (we'll call it L2) is perpendicular to L1, it must, by definition, have a slope of (1/2), so it will have an equation of the general form
y = (x/2) + b2
The midpoint of L1 is given by (x2 + x1)/2 and (y2 + y1)/2 = [(-3) + 3)/2] and [4 + (-8)]/2 or (0, -2)
So L2 will have a slope of (1/2) and pass through the point (0, -2)
This is all the information we need to calculate b2.
y = (x/2) + b2 ⇒ -2 = (0/2) + b2
Therefore b2 = -2, and the complete equation of L2, the perpendicular bisector is:
y = (x/2) - 2