Inactive Tutor answered 02/18/26
Tutor
New to Wyzant
c)= p(3)+p(6)+p(9)+p(12)= 2/36+ 5/36+ 4/36+1/36= 1/3= 33 1/3% chance
Samuel W.
asked 09/28/16Inactive Tutor answered 02/18/26
c)= p(3)+p(6)+p(9)+p(12)= 2/36+ 5/36+ 4/36+1/36= 1/3= 33 1/3% chance
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