Muhammad A. answered 09/26/16
Tutor
0
(0)
Physics-Math Grad, presenting them as simple useful analytical tool
If w(x)=g(x)
4x2+5x-5=2x2-20x+20
2x2+25x-25=0 [ax2+bx+c=0], then solutions for x, x=[-b+-sqroot(b2-4ac)]/2a
With a=2, b=25, c=-25, we find 2 values of x
x1= 0.93, x2= -13.4, are the 2 real values of x