write an equation in slope intercept form for the line that is perpendicular to the given line and that passes through the given point.

y=5-3x;(2,-4)

write an equation in slope intercept form for the line that is perpendicular to the given line and that passes through the given point.

y=5-3x;(2,-4)

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Middletown, CT

Hi Michelle;

y=5-3x...(2,-4)

The slope of the presented equation is -3. This is the coefficient of x. The line perpendicular to such is its negative inverse, 1/3

y=(1/3)x+b

This equation is in the slope-intercept format of...

y=mx+b

m is the slope.

b is the y-intercept, the value of y when x=0.

We can proceed by plugging-in the coordinate provided and thereby establishing b.

Or, we can proceed by using the point-slope formula...

(y-y_{1})=m(x-x_{1})

y--4=(1/3)(x-2)

y+4=(1/3)(x-2)

y+4=(1/3)x-(2/3)

y=(1/3)x-(4 2/3)

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