Arthur D. answered 09/18/16
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cosx/(1+sinx)+(1+sinx)/cosx
cos2x/(1+sinx)(cosx)+(1+sinx)(1+sinx)/(cosx)(1+sinx)
(cos2x+1+2sinx+sin2x)/(cosx)(1+sinx)
(cos2x+sin2x+1+2sinx)/(cosx)(1+sinx)
(1+1+2sinx)/(cosx)(1+sinx)
(2+2sinx)/(cosx)(1+sinx)
(2[1+sinx])/(cosx)(1+sinx)
factor out the two (1+sinx)
2/cosx is the answer