
Kendra F. answered 09/12/16
Tutor
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Patient & Knowledgeable Math & Science Tutor
Hi Sydney,
Since you have an unknown value "k" you can use substitution to solve for (x, y) using the first two equations. Then plug these into the third equation and solve for k.
2x + 3y = 5
x + 4y = 10
x = 10 - 4y (substitute this in for x)
2(10 - 4y) + 3y = 5
20 - 8y + 3y = 5
combine like terms
15 = 5y
y = 3
x + 4(3) = 10
x + 12 = 10
x = -2
So the first two lines intersect at the point (-2, 3)
Use this point in the third equation to find the k value that makes this line also intersect at that same point.
5x + ky = 11
5(-2) + 3k = 11
-10 + 3k = 11
3k = 21
k = 7