Find the slope of a line perpendicular to each given line

Hi Young Friend,

I show you another way for finding slop. If you have Ax+By+C=o that it is one of standard form for line.

It is enough, you find -A/B because it is slop.

3x+4y=8 3x +4y-8=0 slop = -3/4 as you know A=3 , B=4 . Now if you need slop for perpendicular line is

+4/3 and slop for parallel line is -3/4. In fact when two lines are parallel they have the same slop. I hope this explain is useful for you. Please feel free if you have any question.

Be successful,

Minoo

## Comments

taking to the bank. But I have done some research, and Touba is correct. William and I had one oversight. When an equation is in standard form, as is this one, there is an easier technique to calculate slope. Slope is -A/B for an equation in the form of Ax+By=C. The slope of the line perpendicular to it is B/A. Thebankwill recognize that as legal tender.