Fiona L.

asked • 08/23/16

Limits Question

limx->0 (x+sinx)/x
my teacher told me the answer was 2, but I do not know how to get to the answer.

1 Expert Answer

By:

Arturo O. answered • 08/23/16

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Arturo O.

Fiona,
 
Are you familiar with L'Hopital's rule?  Do you need an explanation of it?
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08/23/16

Fiona L.

yes please
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08/23/16

Arturo O.

Fiona,
 
This problem is an example of an indeterminate form.  Both the numerator and denominator approach 0, so it is not obvious what the limiit should be.  L'Hopital's rule says that the limit of a ratio of functions is the same as the limit of the ratio of the derivatives of the functions.  So differentiate both the numerator and denominator, and then try evaluating the limit.
 
In this problem,
 
(x + sin x)' = 1 + cos x
x' = 1
 
So you evaluate the limit as x→0 of the ratio of (1 + cos x)/1.  Notice that after the differentiation, the remaining form is not indeterminate, and you can evaluate the limit.  Sometimes use of L'Hopital's rule produces a second indeterminate form.  You can then try applying the rule successively until you end up with a form that is not indeterminate. 
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08/23/16

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