
David W. answered 08/05/16
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The VERY IMPORTANT piece of information in this and other "combination" problems is that the values seem to be inverted. That is, "1 garden is watered in 3 hours" rather than "3 hours to water the garden."
Rate of first hose + Rate of second hose = Combined rate
(1 garden)/(t/3 hours) + (1 garden)/(t hours) = (1 garden/(3 hours)
3/t + 1/t = 1/3
This resembles (3).
1/x + 3/x = 1/3
3 + 9 = x
12 = x
and
(1/3) x = 4
So, together, a hose that waters at the rate of 12 hours per garden with a hose that waters at the rate of 4 hours per garden can water one garden in 3 hours. [ in 12 hours, that is 1+3 gardens; that is, 12 hours per 4 gardens, or 3 hours for 1 garden, but written as "1 garden in 3 hours"].