please help?

Question

The half-life of carbon-14 is 5,730 years. Assuming you start with 100% of carbon-14, what is the expression for the percent, P(t), of carbon-14 that remains in an organism that is t years old and what is the percent of carbon-14 remaining (rounded to the nearest whole percent) in an organism estimated to be 25,000 years old?

Hint: The exponential equation for half-life is P(t) = A0(0.5)t/H, where P(t) is the percent of carbon-14 remaining, A0 is the initial amount (100%), t is age of the organism in years, and H is the half-life.

P(t) = 100(0.5)5,730t, 23% remaining
P(t) = 100(0.5)5,730/t, 95% remaining
P(t) = 5,730(0.5)100/t, 5,714 remaining
P(t) = 100(0.5)t/5,730, 5% remaining

Answer 1

The hint provides the formula you use:

 

P(t) = a₀(0.5)^t/h

 

P(t) = a₀(0.5)^25000/5730

P(t) = a₀(0.5)^4.363

P(t) ≈ a₀(0.0485966)

P(t)/a₀ ≈ 0.0485966

 

I would select that last choice.