Consider the following equation

Question

Consider the following equation.

y = x^2 - 6

Use the x-values {-1, 0, 1} to find solution points that should be plotted when graphing this equation. (Select all that apply.)

(0, 6)
(-1, -5)
(0, -5)
(-1, -2)
(0, -6)
(1, -5)

Answer 1

y = x²-6

 

This graphs as a parabola opening upward since the coefficient of the square term is positive.

You are merely asking to find the corresponding points on the graph of the parabola for the

values x = {-1, 0, 1}

 

For x = -1, y = (-1)²-6 = 1-6 = -5:  point (-1,-5)

 

For x = 0, y = 0²-6 =-6:  point (0,-6)

 

For x = 1, y = 1²-6 = 1-6 = -5;  point (1,-5)

 

These 3 points are on the graph of the parabola.

 

The vertex of the parabola is at (0,-6) from which point it opens upward to the right and left.