
Vivian L. answered 01/03/14
Microsoft Word/Excel/Outlook, essay composition, math; I LOVE TO TEACH
-[(60 ft)(45 ft)=area of castle]
L O.
asked 01/03/14Vivian L. answered 01/03/14
Microsoft Word/Excel/Outlook, essay composition, math; I LOVE TO TEACH
Miguel M. answered 01/03/14
Math and Science Tutor with 30+ Years Teaching Experience
If the castle has dimensions of 60 ft and 45 ft, then the outer area would have dimensions of 2m +60 and 2m +45, This is because you have the m width of the moat all around the castle, contributing 2m to both width and length. Thus, for #1, area = (2m+60)(2m+45). For #2, substitute 10 ft in for m, and you get area = (80 ft)(65 ft) = 5200 ft^2 For #3, you need the volume for the larger perimeter with a 10 ft depth - the volume for the castle submerged 10 ft. Volume = length x width x height. V(total) = (2m+60)(2m+45)(10). V(submerged castle)= (60)(45)(10) Subtracting,(2m+60)(2m+45)-(27000 ft^3) Plugging in m = 10 ft, (80)(65)(10)-(27000 ft^3) = 52000 ft^3 - 27000 ft^3 = 25000 ft^3. Multiply by 1 gallon/0.134 ft^3 and you get the answer to #3, 186567.164 gallons.
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