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1 Answer

The answer must be the same, 5, because you can use a u-substitution: u=x+c, du=dx.
It yields ∫12--cc f(x) dx = ∫12 f(u-c) dx = 5


Another perspective:

To translate an equation's graph by <h,k> replace all the x's with x-h and all the y's with y-k.

In this case, the translation vector is <-c,0>, and

the function f(x-c) -> f((x--c)-c) = f(x),

the lower bound, x = 1 -> x--c = 1 or x = 1-c, and

the upper bound, x = 2 -> x--c = 2 or x = 2-c.

Since the function and the bounds are simply shifted horizontally on the coordinate plane, the integral value is the same, 5.