1.
This does not require the use of compound inequality concept.
Let the most number of times you enter the zoo = ×
The following inequality can be used to find the most number of times:
22.75× ≤ 71
× ≤ 71/22.75
× ≤ 3.12
Therefore the most number of times you can enter the zoo to pay the entrance fee before spending more than the yearly fee of $71 = 3 times.
Note that your answer cannot be decimal. It has to be an integer. It cannot be 4 because you will end up spending more than $71.
2.
Let the number of boxes required = ×
4.75× ≥ 650
× ≥ 650/4.75
× ≥ 136.84
Therefore, the scout troop must sell at least 137 boxes of cookies to reach their goal.
MICHAEL E.
tutor
Hello Norbert,
Thank you for the comment. I do not know why $4.75 was used. That was an incorrect information. It should have been $4.50, the price per box. The following is the correct solution using $4.50 per box:
4.50x ≥ 650
x ≥ 650/4.50
x ≥ 144.44
Therefore, the scout troop must sell at least 145 boxes of cookies to reach their goal.
I am sorry for not using the right information ($4.50) initially.
Report
07/14/16
Norbert W.
07/13/16