Glenn M. answered 12/30/13
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Invest P dollars at an interest rate of (i), compounded annually, we get the following after one year.
A1 = P + P i = P (1 + i)
after the 2nd year
A2 = A1 (1 + i)
substituting our expression for A1 gives us
A2 = P (1 + i) (1 + i) = P (1 + i)2
Similarly, we can extend this idea to t years and we get
A = P (1 + i)t
now we expand to account for interest being compounded more than once per year say, n times per year. Hence the number of time the interest is compounded will be nt, and the interest rate for a period is i/n.
A(t) = P (1 + i/n)nt
now for your example... P = 1,000, i=9.5%, n=12
A(t) = 1,000 (1 + 0.095/12)12t
and now look at the values for t = 5, 10, 15 years
A(5) = 1,000 (1 + .095/12)12(5)=1,605.01
A(10) = 2,576.06
A(15) = 4,134.59