Hi Sun,

Let's first rearrange to give an expression for y in terms of x:

x^{2} + 2y = 0

Subtracting x^{2} and dividing by 2:

y = (-x^{2})/2

If we plotted this, it would be a downward-opening parabola, centered on the y-axis.

Now, let's come up with an expression that would calculate the distance between a point on that parabola and any other point on the graph. The pythagorean theorem shows us how to calculate the length of the hypotenuse of a right triangle, and that's exactly what we would be dealing with here, if we treat the (difference in the y values) and (difference in x values) as the two perpendicular sides of a triangle.

So, we could say that the actual (hypotenuse) distance between two points would be √((y_{1}-y_{2})^{2} + (x_{1}-x_{2})^{2})

Let's treat x_{1} and y_{1} as the point along the parabola, and x_{2} and y_{2} as the (0, -1/2) point that is given. We want to determine the x_{1} and y_{1} points, so we will leave them as variables in our distance expression:

distance = √((y - (-1/2))^{2} + (x - 0)^{2})

Now, since we have an expression for y in terms of x, let's replace y with that expression, so that we will have only one variable in our equation:

distance = √((-x^{2}/2 + 1/2)^{2} + x^{2})

or

distance = ((-x^{2}/2 + 1/2)^{2} + x^{2})^{1/2}

Let's expand the first squared term, using FOIL:

distance = ((x^{4}/4 - x^{2}/2 + 1/4) + x^{2})^{1/2}

Combining the x^{2} terms:

distance = ((x^{4}/4 + x^{2}/2 + 1/4)^{1/2}

Knowing that we want to find the point where this distance is a minimum, just from examining the equation, the smallest we could ever make this distance would be (1/4)^{1/2} = 1/2, if x = 0. Because of the fact that all of the x exponents are even, any other x-value that we could possibly pick, positive or negative, would only make the distance larger.

So, we know that the distance is minimized when x=0. Since we want to know what the associated y-value is, we plug in 0 for x in the quadratic equation we derived from the given expression.

y = -(0)^{2}/2 = 0

This also checks with what we logically concluded to be the minimum possible distance: the distance between the points (0,0) and (0,-1/2) is 1/2.