Mark M. answered • 06/10/16

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^{x-6}= 7^{2x}log 2

^{x-6}= log 7^{2x}(x - 6)(log 2) = 2x(log 7)

(x)(log 2) - 6(log 2) = 2x(log 7)

-6(log 2) = 2x(log 7) - xlog 2

-6(log2) = x[2log 7 - log 2]

(-6 log 2) / (2log 7 - log 2] = x

This is the exact value.

Anthony Y.

06/10/16