Inactive Tutor answered 12/18/13
Tutor
New to Wyzant
x=1/t; y=t/(t+1)=1/(1+1/t)=1/(1+x)
So y=1/(x+1), obviously x=-1 is an asymptote, another one is y=0, when x goes to infinity.
Sun K.
asked 12/18/13Inactive Tutor answered 12/18/13
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Inactive Tutor
12/19/13