What are the asymptotes of the graph of the parametric equations x=1/t, y=t/(t+1)? Answer: x=-1, y=0. 12/18/2013 | Sun from Los Angeles, CA | 1 Answer | 0 Votes Mark favorite Subscribe Comment
x=1/t; y=t/(t+1)=1/(1+1/t)=1/(1+x) So y=1/(x+1), obviously x=-1 is an asymptote, another one is y=0, when x goes to infinity. 12/18/2013 | Kirill Z. Comment Comments x=-1 is a vertical asymptote (function never crosses a vertical asymptote). y = 0 is a horizontal asymptote, but only at large values of |x| (function may cross horizontal asymptote at small values of |x|). 12/19/2013 | Steve S. Comment
x=-1 is a vertical asymptote (function never crosses a vertical asymptote). y = 0 is a horizontal asymptote, but only at large values of |x| (function may cross horizontal asymptote at small values of |x|). 12/19/2013 | Steve S.
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