
Kenneth S. answered 06/08/16
Tutor
4.8
(62)
Expert Help in Algebra/Trig/(Pre)calculus to Guarantee Success in 2018
These events are INDEPENDENT because the first has no influence on the second--it's just the same to dice, randomly shaken out each time.
P(sum is 10) is = 3/36 = 1/12...because only pairs (4,6), (5,5) and (6,4) total up to ten.
P(sum 9) is 4/36 = 1/9.
The probability of the first event occurring, then followed by the second event, is the product of the above two results.