Roman C. answered 06/04/16
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Masters of Education Graduate with Mathematics Expertise
Recall the linear approximation of f(x) in the neighborhood of x=a is
L(x) = f(a) + f'(a)(x - a)
In this case, f(x) = √(6+5x) = (6+5x)1/2 so:
f'(x) = (6+5x)-1/2 (6+5x)' / 2 = 5/[2√(6+5x)]
So f(0) = √6 and f'(0) = 5/(2√6).
We have:
L(x) = f(0) + f'(0)(x - 0) = √6 + [5/(2√6)]x
A = √6 ; B = 5/(2√6)