Find the slope of the line normal to the curve y=-sqrt(x+4) at the point where x=0.

So I found that the derivative at x=0 is -1/4. Isn't the answer 4 because normal means you need to find the perpendicular of -1/4, right? And I don't need to find the point and the equation for the y-intercept for problems like these since the question just asks for the slope, right?