The length of a rectangle is 2 m longer than its width. If the perimeter of the rectangle is 24 m , find its area.

Question

really bad at word problems need immediate help

Answer 1

 

Let W = width of rectangle

Let W+2 = length of rectangle = L

 

Perimeter = 2L + 2W

          24 = 2L + 2W

 

      since L = W + 2, we can substitute and solve

 

          24 = 2(W + 2) + 2W

          24 = 2W + 4 + 2W

          24 = 4W + 4

          20 = 4W

           W = 5

 

       the length 2 more than 5, which is 7

 

Area = L • W

        = 7•5

        = 12