
Alan G. answered 04/26/16
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log2 x + log2 (x -2) = 3
log2 x(x - 2) = 3
x(x - 2) = 23 = 8
Solving,
x2 - 2x - 8 = 0
(x - 4)(x + 2) = 0
x = 4 or x = -2
The solution -2 is extraneous, since when you insert it into the original equation, both logarithms are undefined (you cannot find the logarithm of a negative number).