Paul B. answered 04/24/16
Tutor
4.9
(126)
I am your advantage in mastering Mathematics and Physics.
There may be something wrong with this problem statement. Neither X nor Y solves as an integer:
We're told that we have two "concutive" positive integers. I believe this is a typo and it really should be "consecutive". So if we call one of the integers X and the next consecutive positive integer Y, then Y=X+1.
Y=X+1
We are told that their product is 14 more than their sum. So, XY=X+Y+14
XY=X+Y+14
We can substitute for Y in terms of X in the second equation using the first equation.
XY=X(X+1) on the left side and
X+(X+1)+14 on the right side, so,
X(X+1)=X+(X+1)+14
Multiplying and gathering terms
X2 +X=2X+1+14
and then simplifying
X2 +X=2X+15
then putting into standard form for quadratic equations, which this IS since there is a variable squared, X2 , but no higher powers
X2 +X-2X-15=0 That is, finally,
X2 -X-15 = 0
This corresponds to the standard quadratic form aX2 + bX + c = 0
with
a = 1
b = -1
c = -15
The quadratic equation for the roots of this equation, for the values that solve it, is
X = [-b ± √b2-4ac]/2a (Check my transcription so you understand the symbology: the square root is of the entire term b2-4ac)
so X = [-(-1)±√((-1)2 - 4(1)(-15))]/2(1)
or
X = [1±√(1+60)]/2 = (1±√61)/2
but
√61 = 7.81,
rounded to two decimal places.
We have
1±7.81
so if X is a positive integer as stated originally, we must ADD that to 1, because subtracting would give a negative quantity.
But
1+7.81 = 8.81
and dividing by 2 (the 2a divisor term in the quadratic formula) gives
X = 4.405 which would make
Y = X+1 = 5.405
Which are NOT integers.
Checking the math
XY = 4.405 x 5.405 = 23.81,
rounded to two decimal places
X + Y + 14 = 4.405 + 5.405 +14 = 23.81
It checks, we solved the equations correctly, Y=X+1 and XY = X+Y+14, but neither X nor Y is an integer.
???
It seems something is wrong with the problem statement.